Two identical thin metal plates has charge $q _{1}$ and $q _{2}$ respectively such that $q _{1}> q _{2}$. The plates were brought close to each other to form a parallel plate capacitor of capacitance $C$. The potential difference between them is.

  • [JEE MAIN 2022]
  • A

    $\frac{\left(q_{1}+q_{2}\right)}{C}$

  • B

    $\frac{\left( q _{1}- q _{2}\right)}{ C }$

  • C

    $\frac{\left(q_{1}-q_{2}\right)}{2 C}$

  • D

    $\frac{2\left(q_{1}-q_{2}\right)}{C}$

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  • [JEE MAIN 2013]

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  • [AIIMS 2009]