Gujarati
2. Electric Potential and Capacitance
easy

The capacity of a parallel plate condenser is $15\,\mu \,F$, when the distance between its plates is $6 \,cm$. If the distance between the plates is reduced to $2\, cm$, then the capacity of this parallel plate condenser will be......$\mu \,F$

A

$15$

B

$30$

C

$45$

D

$60$

Solution

(c) $C \propto \frac{1}{d} \Rightarrow $$\frac{{{C_1}}}{{{C_2}}} = \frac{{{d_2}}}{{{d_1}}}$ $⇒$ $\frac{{15}}{{{C_2}}} = \frac{2}{6} ⇒ C_2 = 45\,\mu F$

Standard 12
Physics

Similar Questions

Start a Free Trial Now

Confusing about what to choose? Our team will schedule a demo shortly.