Two identical thin rings, each of radius $R $ meter are coaxially placed at distance $R$ meter apart. If $Q_1$ and $Q_2$ coulomb are respectively the charges uniformly spread on the two rings, the work done in moving a charge $q$ from the centre of one ring to that of the other is
zero
$q$$\,\left( {{Q_1}\, - \,{Q_2}} \right)\left( {\sqrt 2 \, - \,1} \right)/\left( {\sqrt {2\,} \,.\,4\pi {\varepsilon _0}R} \right)$
$q\,\sqrt 2 \,\left( {{Q_1}\, + \,{Q_2}} \right)/4\pi {\varepsilon _0}R$
$q$$\left( {{Q_1}\, - \,{Q_2}} \right)\left( {\sqrt 2 \, + \,1} \right)/\left( {\sqrt 2 \,.4\pi {\varepsilon _0}R} \right)$
Figure shows a solid metal sphere of radius $‘a’$ surrounded by a concentric thin metal shell of radius $2a$ . Initially both are having charges $Q$ each. When the two are connected by a conducting wire as shown in the figure, then amount of heat produced in this process will be
Four charges are arranged at the corners of a square $ABCD$ of side $d$, as shown in Figure
$(a)$ Find the work required to put together this arrangement.
$(b)$ A charge $q_{0}$ is brought to the centre $E$ of the square, the four charges being held fixed at its corners. How much extra work is needed to do this?
A circle of radius $R$ is drawn with charge $+ q$ at the centre. A charge $q_0$ is brought from point $B$ to $C$, then work done is
The mean free path of electrons in a metal is $4 \times 10^{-8} \;m$. The electric field which can give on an average $2 \;eV$ energy to an electron in the metal will be in units of $V / m$
An alpha particle is accelerated through a potential difference of ${10^6}\,volt$. Its kinetic energy will be......$MeV$