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Question

Electric field due to charge sheet for charge density $+\sigma$ is $E=\frac{+\sigma}{2 \epsilon_{0}}$ and for $-\sigma$ is $E=$$\frac{-\sigma}{2 \epsi

Vedclass · Accepted Answer

$A$ and $C$ both

Vedclass · Answer

Electric field due to charge sheet for charge density $+\sigma$ is $E=\frac{+\sigma}{2 \epsilon_{0}}$ and for $-\sigma$ is $E=$$\frac{-\sigma}{2 \epsilon_{0}}$

outside the plates field is $E=\frac{+\sigma}{2 \epsilon_{0}}+\frac{-\sigma}{2 \epsilon_{0}}=0$

between the plates field is $E=\frac{\sigma}{2 \epsilon_{0}}+\frac{\sigma}{2 \epsilon_{0}}=\frac{\sigma}{\epsilon_{0}}$

Ans: $(\mathrm{A}),(\mathrm{C})$

Two infinite sheets of uniform charge density $+\sigma$ and $-\sigma $ are parallel to each other as shown in the figure. Electric field at the

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