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10-1.Thermometry, Thermal Expansion and Calorimetry
medium
Two liquids $A$ and $B$ are at $32°C$ and $24°C$. When mixed in equal masses the temperature of the mixture is found to be $28°C$. Their specific heats are in the ratio of
A
$3:2$
B
$2:3$
C
$1:1$
D
$4:3$
Solution
(c) Temperature of mixture ${\theta _{mix}} = \frac{{{\theta _A}{c_A} + {\theta _B}{c_B}}}{{{c_A} + {c_B}}}$
$\Rightarrow$ $28 = \frac{{32 \times {c_A} + 24 \times {c_B}}}{{{c_A} + {c_B}}}$
$\Rightarrow$ $28\,{c_A} + 28{c_B} = 32\,{c_A} + 24\,{c_B}$ $\Rightarrow$ $\frac{{{c_A}}}{{{c_B}}} = \frac{1}{1}$
Standard 11
Physics
