Two marks on a glass rod $10\, cm$ apart are found to increase their distance by $0.08\, mm$ when the rod is heated from $0\,^oC$ to $100\,^oC$. A flask made of the same glass as that of rod measures a volume $1000\, cc$ at $0\,^oC$. The volume it measures at $100\,^oC$ in $cc$ is
$1002.4$
$1004.2$
$1006.4$
$1008.2$
A brass rod of length $50\; cm$ and diameter $3.0 \;mm$ is jotned to a steel rod of the same length and diameter. What is the change in length of the combined rod at $250\,^{\circ} C ,$ if the original lengths are at $40.0\,^{\circ} C ?$ Is there a 'thermal stress' developed at the junction? The ends of the rod are free to expand (Co-efficient of linear expansion of brass $=2.0 \times 10^{-5} \;K ^{-1},$ steel $=1.2 \times 10^{-5}\; K ^{-1} J$
Two rods $A$ and $B$ of identical dimensions are at temperature $30\,^oC$. If a heated upto $180\,^oC$ and $B$ upto $T\,^oC$, then the new lengths are the same. If the ratio of the coefficients of linear expansion of $A$ and $B$ is $4:3$, then the value of $T$ is........$^oC$
The pressure $( P )$ and temperature $( T )$ relationship of an ideal gas obeys the equation $PT ^2=$ constant. The volume expansion coefficient of the gas will be:
A sphere of diameter $7\,\, cm$ and mass $266.5 \,\,gm$ floats in a bath of a liquid. As the temperature is raised, the sphere just begins to sink at a temperature $35^o C$. If the density of a liquid at $0^o C$ is $1.527 \,\,gm/cc$, then neglecting the expansion of the sphere, the coefficient of cubical expansion of the liquid is$f$ :
A seconds pendulum clock has a steel wire. The clock shows correct time at $25^{\circ} C$. .......... $s$ time does the clock lose or gain, in one week, when the temperature is increased to $35^{\circ} C$ ? $\left(\alpha_{\text {toel }}=1.2 \times 10^{-5} /{ }^{\circ} C \right)$