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10-1.Thermometry, Thermal Expansion and Calorimetry
medium
Two marks on a glass rod $10\, cm$ apart are found to increase their distance by $0.08\, mm$ when the rod is heated from $0\,^oC$ to $100\,^oC$. A flask made of the same glass as that of rod measures a volume $1000\, cc$ at $0\,^oC$. The volume it measures at $100\,^oC$ in $cc$ is
A
$1002.4$
B
$1004.2$
C
$1006.4$
D
$1008.2$
Solution
In this case, change in length $=0.008 \mathrm{cm}=r_{1} \alpha d t=10 \alpha 100$
so, $\alpha=8 \times 10^{-6} /^{\circ} \mathrm{C}$
So, $\gamma=24 \times 10^{-6} /^{\circ} \mathrm{C}$
Now, $V_{2}=V_{1}(1+\gamma d t)$
Putting the values we get, $V_{2}=1002.4 \mathrm{cc}$
Standard 11
Physics