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At $40\,^oC$, a brass wire of $1\, mm$ is hung from the ceiling. A small mass, $M$ is hung from the free end of the wire. When the wire is cooled down from $40\,^oC$ to $20\,^oC$ it regains its original length of $0.2\, m$. The value of $M$ is close to ........$kg$ (Coefficient of linear expansion and Young's modulus of brass are $10^{-5}/^oC$ and $10^{11}\, N/m^2$, respectively; $g = 10\, ms^{-2}$)
$0.5$
$9$
$0.9$
$1.5$
Solution
$\begin{array}{l}
Mg = \left( {\frac{{Ay}}{l}} \right)\,\Delta l\\
Mg = \left( {Ay} \right)\,\alpha \Delta T = 2\pi
\end{array}$
It is closest to $9$
Similar Questions
A student records the initial length $l$, change in temperature $\Delta T$ and change in length $\Delta l$ of a rod as follows :
S.No. | $l(m)$ | $\Delta T{(^o}C)$ | $\Delta l(m)$ |
$(1)$ | $2$ | $10$ | $4\times 10^{-4}$ |
$(2)$ | $1$ | $10$ | $4\times 10^{-4}$ |
$(3)$ | $2$ | $20$ | $2\times 10^{-4}$ |
$(4)$ | $3$ | $10$ | $6\times 10^{-4}$ |
If the first observation is correct, what can you say about observations $2,\,3$ and $4$.