Gujarati
2. Electric Potential and Capacitance
medium

Two metallic charged spheres whose radii are $20\,cm$ and $10\,cm$ respectively, have each $150\,micro - coulomb$ positive charge. The common potential after they are connected by a conducting wire is

A

$9 \times {10^6}\;volts$

B

$4.5 \times {10^6}\;volts$

C

$1.8 \times {10^7}\;volts$

D

$13.5 \times {10^6}\;volts$

Solution

(a) Common potential $V = \frac{{{\rm{Total \,charge }}}}{{{\rm{Total \,capacitance}}}}$
$V = \frac{{150 \times {{10}^{ – 6}} \times 2}}{{4\pi {\varepsilon _0}(10 \times {{10}^{ – 2}} + 20 \times {{10}^{ – 2}})}} = 9 \times {10^6}\,V$

Standard 12
Physics

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