Gujarati
2. Electric Potential and Capacitance
hard

Two non-conducting spheres of radii $R_1$ and $R_2$ and carrying uniform volume charge densities $+\rho$ and $-\rho$, respectively, are placed such that they partially overlap, as shown in the figure. At all points in the overlapping region: $Image$

$(A)$ the electrostatic field is zero

$(B)$ the electrostatic potential is constant

$(C)$ the electrostatic field is constant in magnitude

$(D)$ the electrostatic field has same direction

A

$(C,D)$

B

$(B,D)$

C

$(B,C)$

D

$(A,C)$

(IIT-2013)

Solution

For electrostatic field,

$\vec{E}_P=\vec{E}_1+\vec{E}_2 $

$=\frac{\rho}{3 \varepsilon_0} \overrightarrow{ C _1 P }+\frac{(-\rho)}{3 \varepsilon_0} \overrightarrow{ C _2 P } $

$=\frac{\rho}{3 \varepsilon_0}\left(\overrightarrow{ C _1 P }+\overrightarrow{ PC _2}\right)$

$\overrightarrow{ E }_{ p }=\frac{\rho}{3 \varepsilon_0} \overrightarrow{ C _1 C _2}$

For electrostatic potential, Since electric field is non zero so it is not equipotential.

Standard 12
Physics

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