Two nuclei have their mass numbers in the rat | vedclass

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Question

$A_{1}: A_{2}=1: 3$

Their radii will be in the ratio

$R_{0} A_{1}^{1 / 3}: R_{0} A_{2}^{1 / 3}=1: 3^{1 / 3}$

Density $=\frac{A}{\frac{4}{3} \

Vedclass · Accepted Answer

$1:1$

Vedclass · Answer

$A_{1}: A_{2}=1: 3$

Their radii will be in the ratio

$R_{0} A_{1}^{1 / 3}: R_{0} A_{2}^{1 / 3}=1: 3^{1 / 3}$

Density $=\frac{A}{\frac{4}{3} \pi R^{3}}$

$	herefore \quad ho_{A_{1}}: ho_{A_{2}}=\frac{1}{\frac{4}{3} \pi R_{0}^{3} \cdot 1^{3}}$ $=\frac{3}{\frac{4}{3} \pi R_{0}^{3}\left(3^{1 / 3}ight)^{3}}$

Their nuclear densities will be the same.

Two nuclei have their mass numbers in the ratio of $1 : 3.$ The ratio of their nuclear densities would be

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