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14.Probability
easy
The probability that an ordinary or a non-leap year has $53$ sunday, is
A
$\frac{2}{7}$
B
$\frac{1}{7}$
C
$\frac{3}{7}$
D
None of these
Solution
(b) In a non-leap year, we have $365$ days $i.e.,$ $52$ weeks and one day.
So, we may have any day of seven days.
Therefore, $53$ Sunday, required probability $= \frac{1}{7}$.
Standard 11
Mathematics
