Two packs of 52 cards are shuffled together. number of ways in which a man can be dealt 26 cards so

English

Gujarati

Hindi

6.Permutation and Combination

medium

Two packs of $52$ cards are shuffled together. The number of ways in which a man can be dealt $26$ cards so that he does not get two cards of the same suit and same denomination is

$^{52}{C_{26}}\;.\;{2^{26}}$

$^{104}{C_{26}}$

$2\;.{\;^{52}}{C_{26}}$

None of these

Solution

(a) $26$ cards can be chosen out of $52$ cards, in $^{52}{C_{26}}$ ways. There are two ways in which each card can be dealt, because a card can be either from the first pack or from the second. Hence the total number of ways ${ = ^{52}}{C_{26}}\;.\;{2^{26}}$.

Standard 11

Mathematics

An urn contains $5$ red marbles, $4$ black marbles and $3$ white marbles. Then the number of ways in which $4$ marbles can be drawn so that at the most three of them are red is

medium

(JEE MAIN-2020)

The number of ways of dividing $52$ cards amongst four players equally, are

easy

(IIT-1979)

In a city no two persons have identical set of teeth and there is no person without a tooth. Also no person has more than $32$ teeth. If we disregard the shape and size of tooth and consider only the positioning of the teeth, then the maximum population of the city is

medium

The number of arrangements that can be formed from the letters $a, b, c, d, e,f$ taken $3$ at a time without repetition and each arrangement containing at least one vowel, is

hard

(AIEEE-2012)

Out of $10$ white, $9$ black and $7$ red balls, the number of ways in which selection of one or more balls can be made, is

medium

Two packs of $52$ cards are shuffled together. The number of ways in which a man can be dealt $26$ cards so that he does not get two cards of the same suit and same denomination is

Solution

Similar Questions

An urn contains $5$ red marbles, $4$ black marbles and $3$ white marbles. Then the number of ways in which $4$ marbles can be drawn so that at the most three of them are red is

The number of ways of dividing $52$ cards amongst four players equally, are

In a city no two persons have identical set of teeth and there is no person without a tooth. Also no person has more than $32$ teeth. If we disregard the shape and size of tooth and consider only the positioning of the teeth, then the maximum population of the city is

The number of arrangements that can be formed from the letters $a, b, c, d, e,f$ taken $3$ at a time without repetition and each arrangement containing at least one vowel, is

Out of $10$ white, $9$ black and $7$ red balls, the number of ways in which selection of one or more balls can be made, is

Start a Free Trial Now