Two particles A and B are projected simultaneously from a fixed point of ground. Particle A is proje

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3-2.Motion in Plane

hard

Two particles $A$ and $B$ are projected simultaneously from a fixed point of the ground. Particle $A$ is projected on a smooth horizontal surface with speed $v$, while particle $B$ is projected in air with speed $\frac{2 v}{\sqrt{3}}$. If particle $B$ hits the particle $A$, the angle of projection of $B$ with the vertical is

A

$30$

B

$60$

C

$45$

D

Both $(a)$ and $(b)$

Solution

(b)

Their horizontal components should be same.

$\therefore \quad \frac{2 v}{\sqrt{3}} \cdot \cos \theta=v$

or $\theta=60^{\circ}$

Standard 11

Physics

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