Angle of projection for a projectile to have same horizontal range and maximum height is

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3-2.Motion in Plane

hard

The angle of projection for a projectile to have same horizontal range and maximum height is

A$\tan ^{-1}(2)$

B$\tan ^{-1}(4)$

C$\tan ^{-1}\left(\frac{1}{4}\right)$

D$\tan ^{-1}\left(\frac{1}{2}\right)$

(JEE MAIN-2024) (AIPMT-2012)

Solution

$\frac{u^2 \sin 2 \theta}{g}=\frac{u^2 \sin ^2 \theta}{2 g}$
$4 \sin \theta \cos \theta=\sin ^2 \theta$
$4=\tan \theta$

Standard 11

Physics

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