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3-2.Motion in Plane
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Two particles are projected from the same point with the same speed at different angles $\theta _1$ and $\theta _2$ to the horizontal. They have the same range. Their times of flight are $t_1$ and $t_2$ respectively.
A
${\theta _1} = 90 - {\theta _2}$
B
$\frac{{{t_1}}}{{\sin \,{\theta _1}}} = \frac{{{t_2}}}{{\sin \,{\theta _2}}}$
C
$\frac{{{t_1}}}{{{t_2}}} = \tan \,{\theta _1}$
D
All of the above
Solution
For same ranges angles of projection are complimentry.
Standard 11
Physics
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