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7.Gravitation
easy
Two planets $A$ and $B$ of radii $R$ and $1.5 R$ have densities $\rho$ and $\rho / 2$ respectively. The ratio of acceleration due to gravity at the surface of $B$ to $A$ is :
A
$2: 3$
B
$2: 1$
C
$3: 4$
D
$4: 3$
(JEE MAIN-2023)
Solution
$g =\frac{ GM }{ R ^2}=\frac{4}{3} \pi G \rho R$
$\therefore \frac{ g _2}{ g _1}=\frac{\rho_2}{\rho_1} \times \frac{ R _2}{ R _1}=\frac{1}{2} \times 1.5=\frac{3}{4}$
Standard 11
Physics