10-2.Transmission of Heat
medium

Two plates $A$ and $B$ have thermal conductivities $84\,Wm ^{-1}\,K ^{-1}$ and $126\,Wm ^{-1}\,K ^{-1}$ respectively. They have same surface area and same thickness. They are placed in contact along their surfaces. If the temperatures of the outer surfaces of $A$ and $B$ are kept at $100^{\circ}\,C$ and $0{ }^{\circ}\,C$ respectively, then the temperature of the surface of contact in steady state is $..........\,{ }^{\circ} C$.

A

$20$

B

$40$

C

$60$

D

$80$

(JEE MAIN-2023)

Solution

Let the temperature of contact surface is $T$, then

$H _{ A }= H _{ B }$

$\frac{ K _{ A } A\left(T_A-T\right)}{L}=\frac{ K _{ B } A \left( T – T _{ B }\right)}{ L }$

$84(100-T)=126( T -0)$

$2(100-T)=3\,T$

$200-2\,T =3\,T$

$T =40^{\circ}\,C$

Standard 11
Physics

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