Two point charges 3 × 10^{-6} ,C and 8 × 10^{-6} , C repel each other by a force of

English

Gujarati

Hindi

1. Electric Charges and Fields

easy

Two point charges $3 \times 10^{-6} \,C$ and $8 \times 10^{-6} \, C$ repel each other by a force of $6 \times 10^{-3} \, N$. If each of them is given an additional charge $-6 \times 10^{-6} \, C$, the force between them will be

$2.4 \times 10^{-3} $ $N$ (attractive)

$2.4 \times 10^{-9} $ $N$ (attractive)

$1.5 \times 10^{-3} $ $N$ (repulsive)

$1.5 \times 10^{-3}$ $N$ (attractive)

Solution

(d)$F \propto {Q_1}{Q_2}$ $==>$ $\frac{{{F_1}}}{{{F_2}}} = \frac{{{Q_1}{Q_2}}}{{{Q_1}'{Q_2}'}}$
$ = \frac{{3 \times {{10}^{ – 6}} \times 8 \times {{10}^{ – 6}}}}{{(3 \times {{10}^{ – 6}} – 6 \times {{10}^{ – 6}})(8 \times {{10}^{ – 6}} – 6 \times {{10}^{ – 6}})}} = \frac{{3 \times 8}}{{ – \,3 \times 2}} = – \frac{4}{1}$
$==>$ ${F_2} = – \frac{{{F_1}}}{4} = – \frac{{6 \times {{10}^{ – 3}}}}{4} = – 1.5 \times {10^{ – 3}}\,N$ (Attractive)

Standard 12

Physics

Write Coulomb’s law and explain its scalar form.

medium

Three charges are placed at the vertices of an equilateral triangle of side ‘$a$’ as shown in the following figure. The force experienced by the charge placed at the vertex $A$ in a direction normal to $BC$ is

medium

(AIIMS-2003)

Two charges $q$ and $-3q$ are placed fixed on $x-axis$ separated by distance $'d'$. Where should a third charge $2q$ be placed such that it will not experience any force ?

medium

A point charge $q_1$ exerts force $F$ upon another point charge $q_2$. If a third charge $q_3$ be placed near the charge $q_2$, then the force that charge $q_1$ exerts on the charge $q_2$ will be

easy

A point charge $q_1=4 q_0$ is placed at origin. Another point charge $q_2=-q_0$ is placed at $x =12\,cm$. Charge of proton is $q_0$. The proton is placed on $x$-axis so that the electrostatic force on the proton in zero. In this situation, the position of the proton from the origin is $……….cm$.

medium

(JEE MAIN-2023)

Two point charges $3 \times 10^{-6} \,C$ and $8 \times 10^{-6} \, C$ repel each other by a force of $6 \times 10^{-3} \, N$. If each of them is given an additional charge $-6 \times 10^{-6} \, C$, the force between them will be

Solution

Similar Questions

Write Coulomb’s law and explain its scalar form.

Three charges are placed at the vertices of an equilateral triangle of side ‘$a$’ as shown in the following figure. The force experienced by the charge placed at the vertex $A$ in a direction normal to $BC$ is

Two charges $q$ and $-3q$ are placed fixed on $x-axis$ separated by distance $'d'$. Where should a third charge $2q$ be placed such that it will not experience any force ?

A point charge $q_1$ exerts force $F$ upon another point charge $q_2$. If a third charge $q_3$ be placed near the charge $q_2$, then the force that charge $q_1$ exerts on the charge $q_2$ will be

Start a Free Trial Now