Two resistors of resistances R₁ = (100 pm 3) ,Ω and R₂ = (200 pm 4) are connected in series. ma

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1.Units, Dimensions and Measurement

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Two resistors of resistances $R_1 = (100 \pm 3) \,\Omega $ and $R_2 = (200 \pm 4)$ are connected in series. The maximm absolute error and percentage error in equivalent resistance of the series combination is

A

$7\, \Omega , 2.3 \%$

B

$1\, \Omega , 0.3 \%$

C

$3\, \Omega , 1 \%$

D

$4\, \Omega , 1.3 \%$

Solution

$R + \Delta R = R_1 + R_2 = (100 \pm 3) + (200 \pm 4) = (300 \pm 7) \Omega$

maximm absolute error $ = \,7 \Omega \,$

$ = \,\frac{{\Delta R}}{R} \times \,100\,\,\, = \,\,\,\,\frac{7}{{300\,}}\,\, \times \,\,100\,\, = \,\,2.3\,\% \,$ પ્રતિશત ત્રુટિ

Standard 11

Physics

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