Gujarati
Hindi
10-2.Transmission of Heat
normal

Two rods of same length and material transfer a given amount of heat in $12\, seconds$, when they are joined end to end. But when they are joined in series, then they will transfer same heat in same conditions in ......... $\sec$

A

$24$

B

$3$

C

$1.5$

D

$48$

Solution

$\frac{\mathrm{dQ}}{12}=\frac{\mathrm{k}(2 \mathrm{A})\left(\mathrm{T}_{1}-\mathrm{T}_{2}\right)}{\ell}$          $…(1)$

$\frac{\mathrm{dQ}}{\mathrm{t}}=\frac{\mathrm{k} \mathrm{A}\left(\mathrm{T}_{1}-\mathrm{T}_{2}\right)}{2 \ell}$             $…(2)$

from $(1)$$\&(2)$ 

$\frac{\mathrm{t}}{12}=4 \quad \mathrm{t}=48 \mathrm{sec}$

Standard 11
Physics

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