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10-2.Transmission of Heat
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Two rods of same length and material transfer a given amount of heat in $12\, seconds$, when they are joined end to end. But when they are joined in series, then they will transfer same heat in same conditions in ......... $\sec$
A
$24$
B
$3$
C
$1.5$
D
$48$
Solution
$\frac{\mathrm{dQ}}{12}=\frac{\mathrm{k}(2 \mathrm{A})\left(\mathrm{T}_{1}-\mathrm{T}_{2}\right)}{\ell}$ $…(1)$
$\frac{\mathrm{dQ}}{\mathrm{t}}=\frac{\mathrm{k} \mathrm{A}\left(\mathrm{T}_{1}-\mathrm{T}_{2}\right)}{2 \ell}$ $…(2)$
from $(1)$$\&(2)$
$\frac{\mathrm{t}}{12}=4 \quad \mathrm{t}=48 \mathrm{sec}$
Standard 11
Physics
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