Gujarati
Hindi
10-2.Transmission of Heat
normal

Two rods of same length and same area of cross section are joined

Temperature of two ends are as shown in figure. As we move along the rod, temperature are as shown in following

A

$K_1 > K_2$

B

$K_1 = K_2$

C

$K_1< K_2$

D

None of these

Solution

$\frac{\mathrm{d} \mathrm{H}}{\mathrm{dt}}=\mathrm{k} \mathrm{A} \frac{\mathrm{dT}}{\mathrm{dx}}$

$\frac{d T}{d x} 1<\frac{d T}{d x} 2$

$\left.\Rightarrow \mathrm{K}_{1}>\mathrm{K}_{2}\right]$

Standard 11
Physics

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