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7.Gravitation
medium
Two satellites $A$ and $B$, having ratio of masses $3 : 1$ are in circular orbits of radius $r$ and $4r$. Calculate the ratio of total mechanical energy of $A$ and $B$.
A
$3 : 4$
B
$12 : 1$
C
$4 : 3$
D
$1 : 12$
Solution
$\because$ total mechanical energy $E=-\frac{\mathrm{GMm}}{2 \mathrm{r}}$
$\therefore \quad \frac{E_{1}}{E_{2}}=\frac{m_{1}}{m_{2}} \times \frac{r_{2}}{r_{1}}=\frac{3}{1} \times \frac{4 r}{r}=\frac{12}{1}$
Standard 11
Physics
