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7.Gravitation
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An object is allowed to fall from a height $R$ above the earth, where $R$ is the radius of earth. Its velocity when it strikes the earth's surface, ignoring air resistance, will be :
A
$2 \sqrt{g R}$
B
$\sqrt{g R}$
C
$\sqrt{\frac{g R}{2}}$
D
$\sqrt{2 g R}$
(JEE MAIN-2023)
Solution
Loss in $PE =$ Gain in $KE$
$\left(-\frac{ GMm }{2 R }\right)-\left(-\frac{ GMm }{ R }\right)=\frac{1}{2} mv ^2$
$\Rightarrow v ^2=\frac{ GM }{ R }= gR$
$\Rightarrow v =\sqrt{ gR }$
Standard 11
Physics
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