Two sheets of thickness d and 3d, are touchin | vedclass

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Question

Given $: L_{A}=d L_{B}=3 d$

As $T_{2}, T_{1}, T_{2} \& T_{3}$ are in arithmetic progression.

$	herefore 2 T_{1}=T_{2}+T_{2} \quad \Longrigh

Vedclass · Accepted Answer

$1 : 3$

Vedclass · Answer

Given $: L_{A}=d L_{B}=3 d$

As $T_{2}, T_{1}, T_{2} \& T_{3}$ are in arithmetic progression.

$	herefore 2 T_{1}=T_{2}+T_{2} \quad \Longrightarrow T_{1}=T_{2}$

Similarly, $2 T_{2}=T_{1}+T_{3}$

OR $\quad 2 T_{2}=T_{2}+T_{3} \quad T_{2}=T_{3}$

Using: $\frac{d Q_{A}}{d t}=\frac{d Q_{B}}{d t}$

$	herefore \frac{K_{A} A\left(T_{1}-T_{2}ight)}{L_{A}}=\frac{K_{B} A\left(T_{2}-T_{3}ight)}{L_{B}}$

OR $\quad \frac{K_{A}}{d}=\frac{K_{B}}{3 d}$

$\Longrightarrow K_{A}: K_{B}=1: 3$

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