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5.Magnetism and Matter
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Two short magnets having magnetic moments in the ratio $27 : 8,$ when placed on opposite sides of a deflection magnetometer, produce no deflection. If the distance of the weaker magnet is $0.12$ $m$ from the centre of deflection magnetometer, the distance of the stronger magnet from the centre is.......$m$
A
$0.06$
B
$0.08 $
C
$0.12$
D
$0.18$
Solution
(d)$\frac{{{M_1}}}{{{M_2}}} = {\left( {\frac{{{d_1}}}{{{d_2}}}} \right)^3} \Rightarrow \frac{{27}}{8} = {\left( {\frac{{{d_1}}}{{0.12}}} \right)^3}$
$ \Rightarrow \frac{3}{2} = \frac{{{d_1}}}{{0.12}} \Rightarrow 0.18\;m$
Standard 12
Physics
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