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Question

(c)For null deflection $\frac{{{M_1}}}{{{M_2}}} = {\left( {\frac{{{d_1}}}{{{d_2}}}} \right)^3} = {\left( {\frac{{40}}{{50}}} \right)^3} = \frac{{64}}{

Vedclass · Accepted Answer

$64 : 125$

Vedclass · Answer

(c)For null deflection $\frac{{{M_1}}}{{{M_2}}} = {\left( {\frac{{{d_1}}}{{{d_2}}}} \right)^3} = {\left( {\frac{{40}}{{50}}} \right)^3} = \frac{{64}}{{125}}$

Two short magnets with their axes horizontal and perpendicular to the magnetic meridian are placed with their centres $40\, cm$ east and $ 50\,cm$ west of magnetic needle. If the needle remains undeflected, the ratio of their magnetic moments ${M_1}:{M_2}$ is

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