Two short magnets with their axes horizontal and perpendicular to magnetic meridian are placed with

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5.Magnetism and Matter

easy

Two short magnets with their axes horizontal and perpendicular to the magnetic meridian are placed with their centres $40\, cm$ east and $ 50\,cm$ west of magnetic needle. If the needle remains undeflected, the ratio of their magnetic moments ${M_1}:{M_2}$ is

$4:5$

$16:25$

$64 : 125$

$2:\sqrt 5 $

Solution

(c)For null deflection $\frac{{{M_1}}}{{{M_2}}} = {\left( {\frac{{{d_1}}}{{{d_2}}}} \right)^3} = {\left( {\frac{{40}}{{50}}} \right)^3} = \frac{{64}}{{125}}$

Standard 12

Physics

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easy

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easy

(AIIMS-2012)

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medium

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medium

Two short magnets with their axes horizontal and perpendicular to the magnetic meridian are placed with their centres $40\, cm$ east and $ 50\,cm$ west of magnetic needle. If the needle remains undeflected, the ratio of their magnetic moments ${M_1}:{M_2}$ is

Solution

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