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3-2.Motion in Plane
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Two stones are projected with the same speed but making different angles with the horizontal. Their ranges are equal. If the angle of projection of one is $\pi /3$ and its maximum height is $h_1$ then the maximum height of the other will be
A
$3h_1$
B
$2h_1$
C
$h_1/2$
D
$h_1/3$
Solution
$\frac{\mathrm{h}_{2}}{\mathrm{h}_{1}}=\frac{\mathrm{u}^{2} \sin ^{2} \theta_{2}}{2 \mathrm{g}} \times \frac{2 \mathrm{g}}{\mathrm{u}^{2} \sin ^{2} \theta_{1}}$
$=\frac{\sin ^{2} \theta_{2}}{\sin ^{2} \theta_{1}}=\frac{\sin ^{2} \pi / 6}{\sin ^{2} \pi / 3}=\frac{1}{3}$
$\therefore \quad \mathrm{h}_{2}=\mathrm{h}_{1} / 3$
Standard 11
Physics
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