Gujarati
Hindi
3-2.Motion in Plane
medium

Two stones are projected with the same speed but making different angles with the horizontal. Their ranges are equal. If the angle of projection of one is $\pi /3$ and its maximum height is $h_1$ then the maximum height of the other will be

A

$3h_1$

B

$2h_1$

C

$h_1/2$

D

$h_1/3$

Solution

$\frac{\mathrm{h}_{2}}{\mathrm{h}_{1}}=\frac{\mathrm{u}^{2} \sin ^{2} \theta_{2}}{2 \mathrm{g}} \times \frac{2 \mathrm{g}}{\mathrm{u}^{2} \sin ^{2} \theta_{1}}$

$=\frac{\sin ^{2} \theta_{2}}{\sin ^{2} \theta_{1}}=\frac{\sin ^{2} \pi / 6}{\sin ^{2} \pi / 3}=\frac{1}{3}$

$\therefore \quad \mathrm{h}_{2}=\mathrm{h}_{1} / 3$

Standard 11
Physics

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