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6.System of Particles and Rotational Motion
hard
Two uniform rods of equal length but different masses are rigidly joined to form an $L$ -shaped body, which is then pivoted as shown. If in equilibrium the body is in the shown configuration, ratio $M/m$ will be:

A
$2$
B
$3$
C
$\sqrt 2 $
D
$\sqrt 3 $
Solution

Taking Moments about point $'O'$
clockwise moments $=$ Anticlockwise moments, $M g \times \frac{l}{2} \sin \left(30^{\circ}\right)=m g \times \frac{l}{2} \sin \left(60^{\circ}\right)$
$\Rightarrow \frac{M}{2}=m \frac{\sqrt{3}}{2}$
$\therefore \frac{M}{m}=\sqrt{3}$
Standard 11
Physics