Two uniform rods of equal length but different masses are rigidly joined to form an $L$ -shaped body, which is then pivoted as shown. If in equilibrium the body is in the shown configuration, ratio $M/m$ will be:

A uniform rod $AB$ is suspended from a point $X$, at a variable distance from $x$ from $A$, as shown. To make the rod horizontal, a mass $m$ is suspended from its end $A$. A set of $(m, x)$ values is recorded. The appropriate variable that give a straight line, when plotted, are

$A$ body is in equilibrium under the influence of a number of forces. Each force has a different line of action. The minimum number of forces required is

$A$ thin rod of length $L$ is placed vertically on a frictionless horizontal floor and released with a negligible push to allow it to fall. At any moment, the rod makes an angle $\theta$ with the vertical. If the center of mass has acceleration $= A$, and the rod an angular acceleration $= \alpha$ at initial moment, then

In an experiment with a beam balance on unknown mass $m$ is balanced by two known mass $m$ is balanced by two known masses of $16\, kg$ and $4\, kg$ as shown in figure. The value of the unknown mass $m$ is ....... $kg$.

For equilibrium of the system, value of mass $m$ should be .......... $kg$