Gujarati
Hindi
6.System of Particles and Rotational Motion
medium

A mass $m$ hangs with the help of a string wrapped around a pulley on a firctionless  bearing. The pulley has mass $m$ and radius $R$. Assuming pulley to be a perfect  uniform circular disc, the acceleration of the mass $m$, if the string does not slip on the  pulley, is:-

A

$\frac{2}{3} g$

B

$\frac{g}{3}$

C

$\frac{3}{2} g$

D

$g$

Solution

$m g-T=m a$

$\mathrm{TR}=\frac{\mathrm{mR}^{2} \alpha}{2}$

$T=\frac{m R \alpha}{2}=\frac{m a}{2}$

$m g-\frac{m a}{2}=m a$

$\frac{3 \mathrm{ma}}{2}=\mathrm{mg}$

$a=\frac{2 g}{3}$

Standard 11
Physics

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