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6.System of Particles and Rotational Motion
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A mass $m$ hangs with the help of a string wrapped around a pulley on a firctionless bearing. The pulley has mass $m$ and radius $R$. Assuming pulley to be a perfect uniform circular disc, the acceleration of the mass $m$, if the string does not slip on the pulley, is:-
A
$\frac{2}{3} g$
B
$\frac{g}{3}$
C
$\frac{3}{2} g$
D
$g$
Solution

$m g-T=m a$
$\mathrm{TR}=\frac{\mathrm{mR}^{2} \alpha}{2}$
$T=\frac{m R \alpha}{2}=\frac{m a}{2}$
$m g-\frac{m a}{2}=m a$
$\frac{3 \mathrm{ma}}{2}=\mathrm{mg}$
$a=\frac{2 g}{3}$
Standard 11
Physics
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