Two unlike charges of magnitude $q$ are separated by a distance $2d$. The potential at a point midway between them is
Zero
$\frac{1}{{4\pi {\varepsilon _0}}}$
$\frac{1}{{4\pi {\varepsilon _0}}}.\frac{q}{d}$
$\frac{1}{{4\pi {\varepsilon _0}}}.\frac{{2q}}{{{d^2}}}$
For a uniformly charged thin spherical shell, the electric potential $(V)$ radially away from the center $(O)$ of shell can be graphically represented as
Consider two charged metallic spheres $S_{1}$ and $\mathrm{S}_{2}$ of radii $\mathrm{R}_{1}$ and $\mathrm{R}_{2},$ respectively. The electric $\left.\text { fields }\left.\mathrm{E}_{1} \text { (on } \mathrm{S}_{1}\right) \text { and } \mathrm{E}_{2} \text { (on } \mathrm{S}_{2}\right)$ on their surfaces are such that $\mathrm{E}_{1} / \mathrm{E}_{2}=\mathrm{R}_{1} / \mathrm{R}_{2} .$ Then the ratio $\left.\mathrm{V}_{1}\left(\mathrm{on}\; \mathrm{S}_{1}\right) / \mathrm{V}_{2} \text { (on } \mathrm{S}_{2}\right)$ of the electrostatic potentials on each sphere is
A thin spherical conducting shell of radius $R$ has a charge $q$ . Another charge $Q$ is placed at the centre of the shell. The electrostatic potential at a point $P$ at a distance $R/2$ from the centre of the shell is
$27$ identical drops are charged at $22\, V\,\,each.$ They combine to form a bigger drop. The potential of the bigger drop will be............ $V.$
Calculate potential on the axis of a ring due to charge $Q$ uniformly distributed along the ring of radius $R$.