Two vectors of magnitude 3 & 4 have resultant which make angle α & β respectively wit

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3-1.Vectors

hard

Two vectors of magnitude $3$ & $4$ have resultant which make angle $\alpha$ & $\beta$ respectively with them $\{given\, \alpha + \beta \neq 90^o\}$

A

$\frac{\sin \alpha}{\sin \beta} = \frac{3}{4}$

B

$\frac{\sin \alpha}{\cos \beta} = \frac{3}{4}$

C

$\frac{\sin \alpha}{\sin \beta} = \frac{4}{3}$

D

None of above

Solution

If we resolve vector of $3$ magnitude and $4$ magnitude along and perpendicular to line of $R$ then

$3 \sin \alpha \text { must cancel } 4 \sin \beta$

$\therefore 3 \sin \alpha=4 \sin \beta$

$\frac{\sin \alpha}{\sin \beta}=\frac{4}{3}$

Standard 11

Physics

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