$ABCDEF$ is a regular hexagon and forces represented in magnitude and direction by $AB, AC,AD, AE$ and $AF$ act at $A$. Their resultant is :
$6\, AD$
$4\, AD$
$3\, AD$
$2\, AD$
Four forces are acting at a point $P$ in equilibrium as shown in figure. The ratio of force $F_{1}$ to $F_{2}$ is $1: x$ where $x =....$
Two forces $P + Q$ and $P -Q$ make angle $2 \alpha$ with each other and their resultant make $\theta$ angle with bisector of angle between them. Then :
A displacement vector of magnitude $4$ makes an angle $30^{\circ}$ with the $x$-axis. Its rectangular components in $x-y$ plane are .........
For the given vector $\vec A =3\hat i -4\hat j+10\hat k$ , the ratio of magnitude of its component on the $x-y$ plane and the component on $z-$ axis is
The magnitude of pairs of displacement vectors are given. Which pair of displacement vectors cannot be added to give a resultant vector of magnitude $13\, cm$?