14.Waves and Sound
medium

Two vibrating strings of the same material but lengths $L$ and $2L$ have radii $2r$ and $r$ respectively. They are stretched under the same tension. Both the strings vibrate in their fundamental modes, the one of length $L$ with frequency $n_1$ and the other with frequency $n_2$. The ratio $n_1/n_2$ is given by

A

$2$

B

$4$

C

$8$

D

$1$

(IIT-2000)

Solution

(d) Fundamental frequency $n = \frac{1}{{2l}}\sqrt {\frac{T}{{\pi {r^2}\rho }}} $ 

where $m =$ Mass per unit length of wire 

==>$n \propto = \frac{1}{{lr}} \Rightarrow \frac{{{n_1}}}{{{n_2}}} = \frac{{{r_2}}}{{{r_1}}} \times \frac{{{l_2}}}{{{l_1}}} = \frac{r}{{2r}} \times \frac{{2L}}{L} = \frac{1}{1}$

Standard 11
Physics

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