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Question

(a)Units of $1st$ rate constant order reaction are $se{c^{ - 1}}$and for zero order reaction, these are $mol\,\,litr{e^{ - 1}}\,\,se{c^{ - 1}}$ i.e. $

Vedclass · Accepted Answer

$se{c^{ - 1}},\,\,\,M\,se{c^{ - 1}}$

Vedclass · Answer

(a)Units of $1st$ rate constant order reaction are $se{c^{ - 1}}$and for zero order reaction, these are $mol\,\,litr{e^{ - 1}}\,\,se{c^{ - 1}}$ i.e. $M\,\,se{c^{ - 1}}$.

Expt. No.	$(A)$	$(B)$	Initial Rate
$1$	$0.012$	$0.035$	$0.10$
$2$	$0.024$	$0.070$	$0.80$
$3$	$0.024$	$0.035$	$0.10$
$4$	$0.012$	$0.070$	$0.80$

units of rate constant of first and zero order reactions in terms of molarity $M$ unit are respectively

Similar Questions

Select the correct statement

For a general reaction $A \to B$, plot of concentration of $A$ vs time is given in figure. Answer the following question on the basis of this graph.

$(i)$ What is the order of the reaction ?

$(ii)$ What is the slope of the curve ?

$(iii)$ What are the units of rate constant ?

Select the rate law that corresponds to the data shown for the following reaction $A+ B\to C$

Expt. No. $(A)$ $(B)$ Initial Rate

$1$ $0.012$ $0.035$ $0.10$

$2$ $0.024$ $0.070$ $0.80$

$3$
$0.024$
$0.035$ $0.10$

$4$ $0.012$ $0.070$ $0.80$

If doubling the initial concentration of reactant doubles $t_{1/2}$ of reaction, the order of reaction is

The reaction $2NO + Br_2 \rightarrow 2NOBr,$ follows the mechanism given below

$(I)$ $NO + Br_2 \rightleftharpoons NOBr_2 $ ........ Fast

$(II)$ $NOBr_2 + NO \rightarrow 2NOBr$ ......... Slow

The overall order of this reaction is