Using suitable identity, solve following: 103^{3}

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2. Polynomials

hard

Using suitable identity, evaluate the following:

$103^{3}$

A

$1090027$

B

$1092700$

C

$1000727$

D

$1092727$

Solution

$103^{3}=(100+3)^{3}$

Now using identify $(a+b)^{3}=a^{3}+b^{3}+3 a b(a+b),$ we have

$(100+3)^{3}=(100)^{3}+(3)^{3}+3(100)(3)(100+3)$

$=1000000+27+900(100+3)$

$=1000000+27+90000+2700$

$=1092727$

Standard 9

Mathematics

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