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6.Permutation and Combination
easy
Value of $r$ for which $^{15}{C_{r + 3}} = {\,^{15}}{C_{2r - 6}}$ is
A
$2$
B
$4$
C
$6$
D
$-9$
Solution
(c) Either $r + 3 = 2r – 6$
or $r + 3 + 2r – 6 = 15,\,\,({\,^n}{C_r} = {\,^n}{C_{n – r}})$
==> $r = 9$ or $r = 6$.
Standard 11
Mathematics