Value of temperature gradient is $80\,^oC/m$ on a rod of $0.5\,m$ length. Temperature of hot end is $30\,^oC$, then what is the temperature of cold end ?
Value of temperature gradient is $80\,^oC/m$ on a rod of $0.5\,m$ length. Temperature of hot end is $30\,^oC$, then what is the temperature of cold end ?
$\frac{\mathrm{T}_{1}-\mathrm{T}_{2}}{\mathrm{~L}}=80$ $30-\mathrm{T}_{2} 80 \times \mathrm{L}$ $=80 \times 0.5$ $30-\mathrm{T}_{2}=40$
$\therefore \mathrm{T}_{2}=30-40$
$\therefore \mathrm{T}_{2}=-10^{\circ} \mathrm{C}$
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