2.Motion in Straight Line
medium

Velocity-time $(v-t)$ graph for a moving object is shown in the figure. Total displacement of the object during the time interval when there is non-zero acceleration and retardation is........$m$

A

$60$

B

$50$

C

$30$

D

$40$

Solution

(b) Between time interval $20\, sec$ to $40\, sec$, there is non-zero acceleration and retardation. Hence distance travelled during this interval

= Area between time interval $20\, sec$ to $40 \,sec$

= $\frac{1}{2} \times 20 \times 3 + 20 \times 1$ $= 30 + 20 = 50 \,m.$

Standard 11
Physics

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