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2.Motion in Straight Line
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Velocity-time $(v-t)$ graph for a moving object is shown in the figure. Total displacement of the object during the time interval when there is non-zero acceleration and retardation is........$m$

A
$60$
B
$50$
C
$30$
D
$40$
Solution
(b) Between time interval $20\, sec$ to $40\, sec$, there is non-zero acceleration and retardation. Hence distance travelled during this interval
= Area between time interval $20\, sec$ to $40 \,sec$
= $\frac{1}{2} \times 20 \times 3 + 20 \times 1$ $= 30 + 20 = 50 \,m.$
Standard 11
Physics
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