The given graph shows the variation of veloci | vedclass

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Question

(a) Given line have positive intercept but negative slope. So its equation can be written as

$v = - mx + {v_0}$&hellip;..(i)      &n

Vedclass · Accepted Answer

Vedclass · Answer

(a) Given line have positive intercept but negative slope. So its equation can be written as

$v = - mx + {v_0}$&hellip;..(i)       [where $m = 	an 	heta = \frac{{{v_0}}}{{{x_0}}}$]

By differentiating with respect to time we get $\frac{{dv}}{{dt}} = - m\frac{{dx}}{{dt}} = - mv$

Now substituting the value of $v$ from eq. (i) we get $\frac{{dv}}{{dt}} = - m[ - mx + {v_0}] = {m^2}x - m{v_0}$

$	herefore a = {m^2}x - m{v_0}$

i.e. the graph between $a$ and $x$ should have positive slope but negative intercept on $a-$axis. So graph $(a) $ is correct.

Colum $I$	Colum $II$
$(A)$ Change in velocity	$(p)$ $-5 / 3\,Sl$ unit
$(B)$ Average acceleration	$(q)$ $-20\,SI$ unit
$(C)$ Total displacement	$(r)$ $-10\,SI$ unit
$(D)$ Acceleration at $t=3\,s$	$(s)$ $-5\,SI$ unit

The given graph shows the variation of velocity with displacement. Which one of the graph given below correctly represents the variation of acceleration with displacement

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