$\therefore p\left(-\frac{1}{\sqrt{3}}\right)=3\left(-\frac{1}{\sqrt{3}}\right)^{2}-1=1-1=0$

$\left[\because\left(-\frac{1}{\sqrt{3}}\right)^{2}=-\frac{1}{\sqrt{3}} \times-\frac{1}{\sqrt{3}}=\frac{1}{3}\right]$

$\therefore p\left(-\frac{1}{\sqrt{3}}\right)=0$

આમ, $x=-\frac{1}{\sqrt{3}}$ એ બહુપદી $3 x^{2}-1$ નું શૂન્ય છે.

$p(x)=3 x^{2}-1$

$\therefore \quad p\left(\frac{2}{\sqrt{3}}\right) =3\left(\frac{2}{\sqrt{3}}\right)^{2}-1 $

$=3\left(\frac{4}{3}\right)-1=4-1=3 $

$ \therefore \quad p\left(\frac{2}{\sqrt{3}}\right) \neq 0 $

આમ, $x=\frac{2}{\sqrt{3}}$ એ બહુપદી $3 x^{2}-1$ નું શૂન્ય નથી.