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Water and turpentine oil (specific heat less than that of water) are both heated to same temperature. Equal amounts of these placed in identical calorimeters are then left in air
Their cooling curves will be identical
$A$ and $B$ will represent cooling curves of water and oil respectively
$B$ and $A$ will represent cooling curves of water and oil respectively
None of the above
Solution
(b) As we know, Rate of cooling $ \propto \frac{{\rm{1}}}{{{\rm{specific}}\;{\rm{heat(c)}}}}$
$\because {c_{{\rm{oil}}}} < {c_{{\rm{Water}}}}$
==> ${({\rm{Rate}}\;{\rm{of}}\;{\rm{cooling}})_{{\rm{oil}}}} > {({\rm{Rate}}\;{\rm{of}}\;{\rm{cooling}})_{{\rm{Water}}}}$
It is clear that, at a particular time after start cooling, temperature of oil will be less than that of water.
So graph $B$ represents the cooling curve of oil and $ A$ represents the cooling curve of water
