What determines nature of path followed by particle

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2.Motion in Straight Line

easy

What determines the nature of the path followed by the particle

ASpeed

BVelocity

CAcceleration

DNone of these

Solution

(d)The nature of the path is decided by the direction of velocity, and the direction of acceleration. The trajectory can be a straight line, circle or a parabola depending on these factors.

Standard 11

Physics

A particle starts moving rectilinearly at time $t = 0$ such that its velocity $'v'$ changes with time $'t'$ according to the equation $v = t^2 – t$ where $t$ is in seconds and $v$ is in $m/s.$ The time interval for which the particle retards is

hard

Velocity of a particle is in negative direction with constant acceleration in positive direction. Then, match the following columns.

Colum $I$ Colum $II$

$(A)$ Velocity-time graph $(p)$ Slope $\rightarrow$ negative

$(B)$ Acceleration-time graph $(q)$ Slope $\rightarrow$ positive

$(C)$ Displacement-time graph $(r)$ Slope $\rightarrow$ zero

$(s)$ $\mid$ Slope $\mid \rightarrow$ increasing

$(t)$ $\mid$ Slope $\mid$ $\rightarrow$ decreasing

$(u)$ |Slope| $\rightarrow$ constant

medium

The diagram shows the variation of $1 / v$ (where, $v$ is velocity of the particle) with respect to time. At time $t=3\,s$ using the details given in the graph, the instantaneous acceleration will be equal to $………..m/s^{2}$

hard

The graph shows the variation with time $t$ of velocity $v$ of an object moving along a straight line. $a-t$ graph will be

medium

The position of a particle moving along the $X-$axis at certain times is given below :Which of the following describes the motion correctly

$\begin{array}{|c|c|c|c|c|} \hline t( s ) & 0 & 1 & 2 & 3 \\ \hline x ( m ) & -2 & 0 & 6 & 16 \\ \hline \end{array} $

medium

Colum $I$	Colum $II$
$(A)$ Velocity-time graph	$(p)$ Slope $\rightarrow$ negative
$(B)$ Acceleration-time graph	$(q)$ Slope $\rightarrow$ positive
$(C)$ Displacement-time graph	$(r)$ Slope $\rightarrow$ zero
	$(s)$ $\mid$ Slope $\mid \rightarrow$ increasing
	$(t)$ $\mid$ Slope $\mid$ $\rightarrow$ decreasing
	$(u)$ \|Slope\| $\rightarrow$ constant

What determines the nature of the path followed by the particle

Solution

Similar Questions

A particle starts moving rectilinearly at time $t = 0$ such that its velocity $'v'$ changes with time $'t'$ according to the equation $v = t^2 – t$ where $t$ is in seconds and $v$ is in $m/s.$ The time interval for which the particle retards is

The diagram shows the variation of $1 / v$ (where, $v$ is velocity of the particle) with respect to time. At time $t=3\,s$ using the details given in the graph, the instantaneous acceleration will be equal to $………..m/s^{2}$

The graph shows the variation with time $t$ of velocity $v$ of an object moving along a straight line. $a-t$ graph will be

The position of a particle moving along the $X-$axis at certain times is given below :Which of the following describes the motion correctly $\begin{array}{|c|c|c|c|c|} \hline t( s ) & 0 & 1 & 2 & 3 \\ \hline x ( m ) & -2 & 0 & 6 & 16 \\ \hline \end{array} $

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The position of a particle moving along the $X-$axis at certain times is given below :Which of the following describes the motion correctly

$\begin{array}{|c|c|c|c|c|} \hline t( s ) & 0 & 1 & 2 & 3 \\ \hline x ( m ) & -2 & 0 & 6 & 16 \\ \hline \end{array} $