What is rolling friction ? Write laws of rolling friction. Define coefficient of rolling friction.
When body is rolling without sliding friction force is called rolling friction. It is denoted by $f_{r}$ Laws of rolling friction :
$(1)$ Magnitude of frictional force do not depend on area of contact.
$(2)$ Magnitude of rolling friction is proportional to normal force.
$f_{s} \propto \mathrm{N}$
$\therefore f_{s}=\mu_{r} \mathrm{~N}$
$u_{r}=\text { co-effil }$
$\mu_{r}=$ co-efficient of rolling friction.
It is unitless,
$\mu_{r}=\frac{f_{r}}{\mathrm{~N}}$
When a ring or a sphere rolling without slipping over a horizontal plane, at every instant there is just one point of contact between the body and the plane and this point has no motion relative to the plane.
In this ideal situation kinetic or static friction is zero and body should move with constant velocity.
But in practise there is some resistance to motion in form of rolling friction hence motion is retarded.
To keep body rolling some applied force is needed.
For, object of given mass rolling friction is $\frac{1}{100}$ or $\frac{1}{1000}$ times static or kinetic friction. Because of this reason discovery of wheel has major milestone in human history. Origin of rolling friction is different than static friction and kinetic friction.
During rolling the surfaces in contact get momentarily deformed a little and small part of body remain in contact with surface.
As a result there is component of the contact force parallel to surface which opposes motion. $\mu_{r}<\mu_{k}<\mu_{s}$
A body of mass $2$ kg is moving on the ground comes to rest after some time. The coefficient of kinetic friction between the body and the ground is $0.2$. The retardation in the body is ...... $m/s^2$
A $500 \,kg$ horse pulls a cart of mass $1500\, kg $ along a level road with an acceleration of $1\,m{s^{ - 2}}$. If the coefficient of sliding friction is $0.2$, then the force exerted by the horse in forward direction is ......... $N$
A body is moving along a rough horizontal surface with an initial velocity $6\,\,m/s.$ If the body comes to rest after travelling $9\, m$, then the coefficient of sliding friction will be
A block of mass $5\,kg$ is placed at rest on a table of rough surface. Now, if a force of $30\,N$ is applied in the direction parallel to surface of the table, the block slides through a distance of $50\,m$ in an interval of time $10\,s$. Coefficient of kinetic friction is (given, $g =10\,ms ^{-2}$)
A fireman of mass $60\, kg$ slides down a pole. He is pressing the pole with a force of $600 \,N$. The coefficient of friction between the hands and the pole is $0.5$, with what acceleration will the fireman slide down ........ $m/s^2$