- Home
- Standard 11
- Physics
4-2.Friction
medium
A horizontal force of $129.4 \,N $ is applied on a $10\, kg$ block which rests on a horizontal surface. If the coefficient of friction is $0.3$, the acceleration should be ....... $m/s^2$
A
$9.8$
B
$10$
C
$12.6$
D
$19.6$
Solution
(b) From the relation $F – \mu mg = ma$
$a = \frac{{F – \mu mg}}{m} = \frac{{129.4 – 0.3 \times 10 \times 9.8}}{{10}} = 10\;m/{s^2}$
Standard 11
Physics