What is the maximum value of the force F such | vedclass

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Question

$\mathrm{F} \cos 	heta=\mathrm{f}$

$\mathrm{F} \cos 	heta=\mu(\mathrm{N})$

$\mathrm{F} \cos 	heta=\mu(\mathrm{F} \sin 	heta+\mathrm{mg})$

Vedclass · Accepted Answer

$20$

Vedclass · Answer

$\mathrm{F} \cos 	heta=\mathrm{f}$

$\mathrm{F} \cos 	heta=\mu(\mathrm{N})$

$\mathrm{F} \cos 	heta=\mu(\mathrm{F} \sin 	heta+\mathrm{mg})$

$(\mathrm{F} \cos 	heta-\mu \mathrm{F} \sin 	heta)=\mu \mathrm{mg}$

$F=\frac{\mu m g}{\cos 	heta-\mu \sin 	heta}$

$\mathrm{F}=\frac{\frac{1}{2 \sqrt{3}} \cdot \sqrt{3} 	imes 10}{\frac{1}{2}-\frac{1}{2 \sqrt{3}} 	imes \frac{\sqrt{3}}{2}}$

$\mathrm{F} \Rightarrow 5 	imes 4=20 \mathrm{N}$

What is the maximum value of the force $F$ such that the block shown in the arrangement does not move ....... $N$

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