Molar solubility of Fe(OH)₂ (K_{sp} = 8.0 × 10^{-16}) at pH,,13.0 ?

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6-2.Equilibrium-II (Ionic Equilibrium)

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What is the molar solubility of $Fe(OH)_2$ $(K_{sp} = 8.0 \times 10^{-16})$ at $pH\,\,13.0$ ?

A

$8.0 \times 10^{-18}$

B

$8.0 \times 10^{-15}$

C

$8.0 \times 10^{-17}$

D

$8.0 \times 10^{-14}$

Solution

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Standard 11

Chemistry

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