Gujarati
6-2.Equilibrium-II (Ionic Equilibrium)
medium

If ${K_{sp}}$ for $HgS{O_4}$ is $6.4 \times {10^{ - 5}},$ then solubility of the salt is

A

$8 \times {10^{ - 3}}$

B

$8 \times {10^{ - 6}}$

C

$6.4 \times {10^{ - 5}}$

D

$6.4 \times {10^{ - 3}}$

Solution

(a) $HgS{O_4}$ of ${K_{sp}} = {S^2}$

$S = \sqrt {{K_{sp}}} $ ; $S = \sqrt {6.4 \times {{10}^{ – 5}}} $; $S = 8 \times {10^{ – 3}}\,m/l$.

Standard 11
Chemistry

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