What is the number of ways of choosing $4$ cards from a pack of $52$ playing cards? In how many of these
are face cards,
There will be as many ways of choosing $4$ cards from $52$ cards as there are combinations of $52$ different things, taken $4$ at a time. Therefore
The required number of ways $=\,\,^{52} C _{4}=\frac{52 !}{4 ! 48 !}=\frac{49 \times 50 \times 51 \times 52}{2 \times 3 \times 4}$
$=270725$
There are $12$ face cards and $4$ are to be selected out of these $12$ cards. This can be done in $^{12} C _{4}$ ways.
Therefore, the required number of ways $=\frac{12 !}{4 ! 8 !}=495$
How many words can be made from the letters of the word $BHARAT$ in which $ B $ and $H$ never come together
A country has ten smart cities. The government decides to connect all these cities by road. How many roads the government need to construct so that every city is connected to every other city ?
If $^n{C_3} + {\,^n}{C_4} > {\,^{n + 1}}{C_3},$ then
The number of four-letter words that can be formed with letters $a, b, c$ such that all three letters occur is
The number of ways of dividing $52$ cards amongst four players so that three players have $17$ cards each and the fourth player just one card, is