What is the order of reaction $r\, = \,k{[A]^{\frac{3}{2}}}\,{[B]^2}$ ?
What is the order of reaction $r\, = \,k{[A]^{\frac{3}{2}}}\,{[B]^2}$ ?
Similar Questions
In a reaction, $2X \to Y$ , the concentration of $X$ decreases from $0.50\, M$ to $0.38\, M$ in $10\, min$ . what is the rate of reaction in $Ms^{-1}$ during the interval ?
In a reaction, $2X \to Y$ , the concentration of $X$ decreases from $0.50\, M$ to $0.38\, M$ in $10\, min$ . what is the rate of reaction in $Ms^{-1}$ during the interval ?
The rate constant for the reaction, $2N_2O_5 \to 4NO_2 + O_2$ is $3.0\times 10^{- 4}\,s^{-1}$ . If start made with $1.0\,mol\,L^{-1}$ of $N_2O_5$, calculate the rate of formation of $NO_2$ at the moment of the reaction when concentration of $O_2$ is $0.1\, mol\, L^{-1}$.
The rate constant for the reaction, $2N_2O_5 \to 4NO_2 + O_2$ is $3.0\times 10^{- 4}\,s^{-1}$ . If start made with $1.0\,mol\,L^{-1}$ of $N_2O_5$, calculate the rate of formation of $NO_2$ at the moment of the reaction when concentration of $O_2$ is $0.1\, mol\, L^{-1}$.
- [AIIMS 2011]
The rate of certain reaction depends on concentration according to the equation $\frac{{ - dc}}{{dt}} = \frac{{{K_1}C}}{{1 + {K_2}C}},$ what is the order, when concentration $(c)$ is very-very high
The rate of certain reaction depends on concentration according to the equation $\frac{{ - dc}}{{dt}} = \frac{{{K_1}C}}{{1 + {K_2}C}},$ what is the order, when concentration $(c)$ is very-very high
units of rate constant of first and zero order reactions in terms of molarity $M$ unit are respectively
units of rate constant of first and zero order reactions in terms of molarity $M$ unit are respectively
- [AIEEE 2002]
The rate of the simple reaction, $2NO + O_2 \to 2NO_2$, when the volume of the reaction vessel is doubled
The rate of the simple reaction, $2NO + O_2 \to 2NO_2$, when the volume of the reaction vessel is doubled