8.Mechanical Properties of Solids
medium

What is Young’s modulus ? Explain. and Give its unit and dimensional formula.

Option A
Option B
Option C
Option D

Solution

Experimental observation show that for a given material the magnitude of the strain produced is same whether the stress is tensile or compressive.

The ratio of tensile (or compressive) stress $(\sigma)$ to the longitudinal strain $(\varepsilon)$ is defined as Young's modulus and is denoted by the symbol Y.

$\text { Young modulus }=\frac{\text { Tensile stress }(\sigma)}{\text { Longitudinal } \operatorname{strain}(\varepsilon)}$

$\quad \mathrm{Y}=\frac{\sigma}{\varepsilon}$

$\therefore \mathrm{Y}=\frac{(\mathrm{F} / \mathrm{A})}{(\Delta \mathrm{L} / \mathrm{L})}=\frac{(\mathrm{F} \times \mathrm{L})}{(\mathrm{A} \times \Delta \mathrm{L})}$

Here, strain is a dimensionless quantity, the unit of Young's modulus is the same as that of stress. Mean $\mathrm{N} \mathrm{m}^{-2}$ or Pascal $(\mathrm{P} a)$.

Dimensional formula : $\left[\mathrm{M}^{1} \mathrm{~L}^{-1} \mathrm{~T}^{-2}\right]$.

Young's moduli, elastic limit and tensile strength of some materials are given below.

Substance

Young's

Modulus

$10^{9} \mathrm{~N} / \mathrm{m}^{2}$

$\sigma_{y}$

Elastic

limit

$10^{7} \mathrm{~N} / \mathrm{m}^{2}$

$%$

Tensile 

strength

$10^{7} \mathrm{~N} / \mathrm{m}^{2}$

$\sigma_{u}$

Aluminium $70$ $18$ $20$
Copper $120$ $20$ $40$
Iron (Wrought) $190$ $17$ $33$
Steel $200$ $30$ $50$

Bone

(Tensile)

(Compressive)

$16$

$9$

 

$12$

$12$

For metals Young's moduli are large therefore these materials require a large force produce small change in length.

Steel is more elastic than copper, brass and aluminium. It is for this reason that steel is preferred in heavy-duty machines and in structural designs.

Wood, bone, concrete and glass have rather small Young's moduli.

Standard 11
Physics

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