What is Young’s modulus ? Explain. and Give its unit and dimensional formula.
Experimental observation show that for a given material the magnitude of the strain produced is same whether the stress is tensile or compressive.
The ratio of tensile (or compressive) stress $(\sigma)$ to the longitudinal strain $(\varepsilon)$ is defined as Young's modulus and is denoted by the symbol Y.
$\text { Young modulus }=\frac{\text { Tensile stress }(\sigma)}{\text { Longitudinal } \operatorname{strain}(\varepsilon)}$
$\quad \mathrm{Y}=\frac{\sigma}{\varepsilon}$
$\therefore \mathrm{Y}=\frac{(\mathrm{F} / \mathrm{A})}{(\Delta \mathrm{L} / \mathrm{L})}=\frac{(\mathrm{F} \times \mathrm{L})}{(\mathrm{A} \times \Delta \mathrm{L})}$
Here, strain is a dimensionless quantity, the unit of Young's modulus is the same as that of stress. Mean $\mathrm{N} \mathrm{m}^{-2}$ or Pascal $(\mathrm{P} a)$.
Dimensional formula : $\left[\mathrm{M}^{1} \mathrm{~L}^{-1} \mathrm{~T}^{-2}\right]$.
Young's moduli, elastic limit and tensile strength of some materials are given below.
Substance |
Young's Modulus $10^{9} \mathrm{~N} / \mathrm{m}^{2}$ $\sigma_{y}$ |
Elastic limit $10^{7} \mathrm{~N} / \mathrm{m}^{2}$ $%$ |
Tensile strength $10^{7} \mathrm{~N} / \mathrm{m}^{2}$ $\sigma_{u}$ |
Aluminium | $70$ | $18$ | $20$ |
Copper | $120$ | $20$ | $40$ |
Iron (Wrought) | $190$ | $17$ | $33$ |
Steel | $200$ | $30$ | $50$ |
Bone (Tensile) (Compressive) |
$16$ $9$ |
$12$ $12$ |
For metals Young's moduli are large therefore these materials require a large force produce small change in length.
Steel is more elastic than copper, brass and aluminium. It is for this reason that steel is preferred in heavy-duty machines and in structural designs.
Wood, bone, concrete and glass have rather small Young's moduli.
A wooden wheel of radius $R$ is made of two semicircular part (see figure). The two parts are held together by a ring made of a metal strip of cross section area $S$ and length $L$. $L$ is slighly less than $2\pi R$. To fit the ring on the wheel, it is heated so that its temperature rises by $\Delta T$ and it just steps over the wheel.As it cools down to surronding temperature, it presses the semicircular parts together. If the coefficint of linear expansion of the metal is $\alpha$, and its young's modulus is $Y$, the force that one part of wheel applies on the other part is
A wire elongates by $l$ $mm$ when a load $W$ is hanged from it. If the wire goes over a pulley and two weights $W$ each are hung at the two ends, the elongation of the wire will be (in $mm$)
Column$-II$ is related to Column$-I$. Join them appropriately :
Column $-I$ | Column $-II$ |
$(a)$ When temperature raised Young’s modulus of body | $(i)$ Zero |
$(b)$ Young’s modulus for air | $(ii)$ Infinite |
$(iii)$ Decreases | |
$(iv)$Increases |
A steel wire is $1 \,m$ long and $1 \,mm ^2$ in area of cross-section. If it takes $200 \,N$ to stretch this wire by $1 \,mm$, how much force will be required to stretch a wire of the same material as well as diameter from its normal length of $10 \,m$ to a length of $1002 \,cm$ is ........ $N$
A stone is tied to an elastic string of negligible mass and spring constant $k$. The unstretched length of the string is $L$ and has negligible mass. The other end of the string is fixed to a nail at a point $P$. Initially the stone is at the same level as the point $P$. The stone is dropped vertically from point $P$.
$(a)$ Find the distance $'y'$ from the top when the mass comes to rest for an instant, for the first time.
$(b)$ What is the maximum velocity attained by the stone in this drop ?
$(c)$ What shall be the nature of the motion after the stone has reached its lowest point ?